In VC2012, I want to create a mutex in a constructor using a unique pointer and a deleter, so that I don't need to create a destructor just to call CloseHandle.
I would have thought that this would work:
struct foo
{
std::unique_ptr<HANDLE, BOOL(*)(HANDLE)> m_mutex;
foo() : m_mutex(CreateMutex(NULL, FALSE, NULL), CloseHandle) {}
}
but on compiling I get an error:
error C2664: 'std::unique_ptr<_Ty,_Dx>::unique_ptr(void *,int
(__cdecl *const &)(HANDLE)) throw()' : cannot convert parameter 1 from
'HANDLE' to 'void *'
When I modify the constructor thus:
foo() : m_mutex((void*)CreateMutex(NULL, FALSE,
(name + " buffer mutex").c_str()), CloseHandle) {}
I get the even more unusual:
error C2664: 'std::unique_ptr<_Ty,_Dx>::unique_ptr(void *,
int (__cdecl *const &)(HANDLE)) throw()' : cannot convert
parameter 1 from 'void *' to 'void *'
I'm at a loss now. HANDLE is a typedef for void*: is there some conversion magic I need to know about?
Forget about the custom deleter for now. When you say std::unique_ptr<T>
, the unique_ptr
constructor expects to receive a T*
, but CreateMutex
returns a HANDLE
, not a HANDLE *
.
There are 3 ways to fix this:
std::unique_ptr<void, deleter> m_mutex;
You'll have to cast the return value of CreateMutex
to a void *
.
Another way to do this is use std::remove_pointer
to get to the HANDLE
's underlying type.
std::unique_ptr<std::remove_pointer<HANDLE>::type, deleter> m_mutex;
Yet another way to do this is to exploit the fact that if the unique_ptr
's deleter contains a nested type named pointer
, then the unique_ptr
will use that type for its managed object pointer instead of T*
.
struct mutex_deleter {
void operator()( HANDLE h )
{
::CloseHandle( h );
}
typedef HANDLE pointer;
};
std::unique_ptr<HANDLE, mutex_deleter> m_mutex;
foo() : m_mutex(::CreateMutex(NULL, FALSE, NULL), mutex_deleter()) {}
Now, if you want to pass a pointer to function type as the deleter, then when dealing with the Windows API you also need to pay attention to the calling convention when creating function pointers.
So, a function pointer to CloseHandle
must look like this
BOOL(WINAPI *)(HANDLE)
Combining all of it,
std::unique_ptr<std::remove_pointer<HANDLE>::type,
BOOL(WINAPI *)(HANDLE)> m_mutex(::CreateMutex(NULL, FALSE, NULL),
&::CloseHandle);
I find it easier to use a lambda instead
std::unique_ptr<std::remove_pointer<HANDLE>::type,
void(*)( HANDLE )> m_mutex;
foo() : m_mutex(::CreateMutex(NULL, FALSE, NULL),
[]( HANDLE h ) { ::CloseHandle( h ); }) {}
Or as suggested by @hjmd in the comments, use decltype
to deduce the type of the function pointer.
std::unique_ptr<std::remove_pointer<HANDLE>::type,
decltype(&::CloseHandle)> m_mutex(::CreateMutex(NULL, FALSE, NULL),
&::CloseHandle);