I have form to upload images.. what i want is to process the form by ajax and after success show jquery thickbox..
do the ajax-call, and define a callback-function.
In the callback-function call this method:
function tb_show(caption, url, imageGroup)
this normally should show the tickbox
Make the ajax-call:
$.ajax({
url: "yoururl.php",
cache: false,
success: function(){ // --> this defines what function needs to be called when the ajaxcall was successful.
// note that you'll need to fill the variables caption, url and imagegroup here. I don't know what they should be in your case.
function tb_show(caption, url, imageGroup);
}
});