Given a matrix where 1 is the current subset
test =
0 0 0 0 0 0
0 0 0 0 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 0 0 0 0
0 0 0 0 0 0
Is there a function, or quick method to get change the subset to the boundary of the current subset?
Eg. Get this subset from 'test' above
test =
0 0 0 0 0 0
0 1 1 1 1 0
0 1 0 0 1 0
0 1 0 0 1 0
0 1 1 1 1 0
0 0 0 0 0 0
In the end I just want to get the minimum of the cells surrounding a subset of a matrix. Sure I could loop through and get the minimum of the boundary (cell by cell), but there must be a way to do it with the method i've shown above.
Note the subset WILL be connected, but may not be rectangular. This may be the big catch.
This is a possible subset.... (Would pad this with a NaN border)
test =
0 0 0 0 0 0
0 0 0 0 0 0
0 0 1 1 0 0
0 0 1 1 0 0
0 0 1 1 1 1
0 0 1 1 1 1
Ideas?
The basic steps I'd use are:
What I want to do here is pass a 3x3 window over each cell and take the maximum value in that window:
[m, n] = size(A); % assuming A is your original shape matrix
APadded = zeros(m + 2, n + 2);
APadded(2:end-1, 2:end-1) = A; % pad A with zeroes on each side
ADilated = zeros(m + 2, n + 2); % this will hold the dilated shape.
for i = 1:m
for j = 1:n
mask = zeros(size(APadded));
mask(i:i+2, j:j+2) = 1; % this places a 3x3 square of 1's around (i, j)
ADilated(i + 1, j + 1) = max(APadded(mask));
end
end
This is basically a logical AND and a logical NOT to remove the intersection:
ABoundary = ADilated & (~APadded);
At this stage you may want to remove the border we added to do the dilation, since we don't need it any more.
ABoundary = ABoundary(2:end-1, 2:end-1);
We can use our logical boundary to index the original data into a vector, then just take the minimum of that vector.
dataMinimum = min(data(ABoundary));