This is a problem that happens when you are in the follow situation: -Have a main window in my application -I create another window that doesn't show in task bar, and is a tool window. -I show the second window as a dialog window (from the main window) -I switch to another application running in my system, and when i came back to the application the main window is showed, but it is locked by the second windows, that is not showed.
This is the code of the second window:
<Window x:Class="WpfApplication1.DialogWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="DialogWindow" Height="300" Width="300" WindowStartupLocation="CenterScreen" WindowStyle="ToolWindow" ShowInTaskbar="False">
<!--Some content-->
</Windows>
And this is the code that shows the second window:
private void Button_Click_1(object sender, RoutedEventArgs e)
{
var dialogWindow = new DialogWindow();
dialogWindow.ShowDialog();
}
How can i solve this problem, and still showing a dialog windows that doesn't shows in task bar?
I think you should set the DialogWindow.Owner
property to the parent window. See this answer WPF: How do I set the Owner Window of a Dialog shown by a UserControl?
private void Button_Click_1(object sender, RoutedEventArgs e)
{
var dialogWindow = new DialogWindow();
dialogWindow.Owner = Window.GetWindow(this)
dialogWindow.ShowDialog();
}
That should put the DialogWindow
modally in front of its parent at all times.