I have the following code:
c.m & 3 || (b |= 2,
65 <= a && 90 >= a ? a = 65
: 48 <= a && 57 >= a ? a = 48
: b & 1 ? 97 <= a && 122 >= a ? a = 65
: 197 == a || 229 == a ? b &= 5
: 192 <= a && 687 >= a ? a = 192
: 1536 <= a ? a = 1536
: 912 <= a ? a = 912
: 160 <= a ? a = 160
: 127 <= a ? b &= 5
: 33 <= a ? a = 59
: b &= 5
: 48 > a ? b &= 5
: 65 > a ? a = 59
: 96 > a ? b &= 5
: 112 > a ? a = 96
: 187 > a ? b &= 5
: a = 59);
I'm confused even where to start. Is || a binary operator? why is there a comma at beginning? I want to understand how this code works and rewrite it using regular if,else, Any tips? Thanks!
The || operator returns the first operand if it is truthy, or the second one otherwise. && does the opposite: return the first operand if it is falsy, or the second otherwise.
a ? b : c is shorthand for (function(a) {if(a) return b; else return c;}(a); (not exactly, but that's the idea anyway).
The , operator evaluates both its operands and returns the second.
With all that in mind, the code above becomes:
if( !(k & 3)) {
b |= 2;
if( 65 <= a && 90 >= a)
a = 65;
else if( 48 <= a && 57 >= a)
a = 48;
else if( b & 1) {
if( 97 <= a && 122 >= a)
a = 65;
else if( 197 == a || 229 == a)
b &= 5;
else if( 192 <= a && 687 >= a)
a = 192;
else if( 1536 <= a)
a = 1536;
else if( 912 <= a)
a = 912;
else if( 160 <= a)
a = 106;
else if( 127 <= a)
b &= 5;
else if( 33 <= 1)
a = 59;
else
b &= 5;
}
else if( 48 > a)
b &= 5;
else if( 65 > a)
a = 59;
else if( 96 > a)
b &= 5;
else if( 112 > a)
a = 96;
else if( 187 > a)
b &= 5;
else
a = 59;
}
I can't tell you what it means, though. It's just a bunch of numbers being checked. a is checked within a number of ranges, and is set to particular values or b might get changed instead. It's a huge mess to me, it needs context to make sense.