How can I express that an argument needs to implement multiple interfaces in C#

Question

Similiar to this question: How can I require a method argument to implement multiple interfaces? I want a method argument to implement several interfaces.

The interfaces shall be combinable in arbitrary fashion and I don't want to create an interface for each valid combination.

Think of a file. It can be:

1. readable => IReadable
2. writeable => IWriteable
3. an archive => IArchive
4. automatically generated => IGenerated

...

If I want to express that an argument needs to be an writable, generated archive I don't want to generate IWritableGeneratedArchive since there are too combinations and I want to use it with some existing classes I cannot modify.

Pseudocode:

void WriteTo( IWritable + IGenerated + IArchive file)
{
   //...
}

Answer 1

The solution I found here: How can I require a method argument to implement multiple interfaces? adjusted for C#.

Credits go to Michael Myers

internal interface IF1
{
    void M1();
}

internal interface IF2
{
    void M2();
}

internal class ClassImplementingIF1IF2 : IF1, IF2
{

    public void M1()
    {
        throw new NotImplementedException();
    }

    public void M2()
    {
        throw new NotImplementedException();
    }

}

internal static class Test
{

    public static void doIT<T>(T t) where T:IF1,IF2
    {
        t.M1();
        t.M2();
    }

    public static void test()
    {
        var c = new ClassImplementingIF1IF2();
        doIT(c);
    }
}