How to get immediately following siblings up to next unmatched selector

Question

I have the following table

<table id="table">
<tr><td>Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr><td>Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr><td>Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr class="hide"><td>Hidden Item</td></tr>
<tr><td>Item</td></tr>
</table>

on clicking on a visible row, i want to show all the immediately following hidden rows up to the next visible row. The number of hidden rows is not fixed. How can I select immediately following rows up to a specific element?

Answer 1

//Add a class to your visible rows if possible to replace the next selector
$('tr:visible').click(function() {
    $('.hide').hide();
    $(this).nextUntil(':visible').fadeIn();
});​

Fiddle

.nextUntil() Reference

---

Adding a show class to the visible rows, you can add a simple toggle effect to it:

$('.show').click(function() {
    $(this).nextUntil('.show').not('.show').fadeToggle();
});

Fiddle

---

A slightly more elaborated version which toggles the clicked rows' section and hides the rows which were previously open:

$('.show').click(function() {
    $('.hide').not(
        $(this).nextUntil('.show').not('.show').fadeToggle()
    ).hide();
});

Fiddle