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javadatecalendargregorian-calendar

Organise number of days into separate sections for year, months, days, hours. Java


is there a way of organising a number of days calculated by working out the difference between two dates, into different sections e.g. for 364 days it would be: 0 years, 11 months, 30 days, hours, minutes etc. I thought using logical operators may work like % and / but as different months have different amounts of days and some years are leap years i'm not sure how to do it. Any help would be much appreciated. My code:

import java.util.*;

public class CleanDate {

    public static void main(String[] args) {
        Calendar cDate = GregorianCalendar.getInstance();
        cDate.set(2011, 0, 31, 00, 00, 00);
        Date date1 = cDate.getTime();
        Date date2 = new Date();
        Calendar calendar1 = Calendar.getInstance();
        Calendar calendar2 = Calendar.getInstance();
        calendar1.setTime(date1);
        calendar2.setTime(date2);
        long milliseconds1 = calendar1.getTimeInMillis();
        long milliseconds2 = calendar2.getTimeInMillis();
        long diff = milliseconds2 - milliseconds1;
        long diffSeconds = diff / 1000;
        long diffMinutes = diff / (60 * 1000);
        long diffHours = diff / (60 * 60 * 1000);
        long diffDays = diff / (24 * 60 * 60 * 1000);
        System.out.println("Time in minutes: " + diffMinutes + " minutes.");
        System.out.println("Time in hours: " + diffHours + " hours.");
        System.out.println("Time in days: " + diffDays + " days.");
    }
}

Solution

  • You could effectively use Joda Time like this: Interval allows to get time interval between two dates.

    DateTime end = new DateTime(2006, 1, 1, 0, 0, 0, 0);
    Interval interval = new Interval(start, end);
    Period period = interval.toPeriod();
    System.out.println(period.getYears()+" years, "
    period.getMonths()+" months, "+period.getWeeks()+" weeks, "+period.getDays()+", days");