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jsonscalaplayframeworkplayframework-2.0playframework-json

serializing objects to json with play.api.libs.json


I'm trying to serialize some relatively simple models into json. For example, I'd like to get the json representation of:

case class User(val id: Long, val firstName: String, val lastName: String, val email: Option[String]) {
    def this() = this(0, "","", Some(""))
}

Do i need to write my own Format[User] with the appropriate reads and writes methods or is there some other way? I've looked at https://github.com/playframework/Play20/wiki/Scalajson but I'm still a bit lost.


Solution

  • Yes, writing your own Format instance is the recommended approach. Given the following class, for example:

    case class User(
      id: Long, 
      firstName: String,
      lastName: String,
      email: Option[String]
    ) {
      def this() = this(0, "","", Some(""))
    }
    

    The instance might look like this:

    import play.api.libs.json._
    
    implicit object UserFormat extends Format[User] {
      def reads(json: JsValue) = User(
        (json \ "id").as[Long],
        (json \ "firstName").as[String],
        (json \ "lastName").as[String],
        (json \ "email").as[Option[String]]
      )
    
      def writes(user: User) = JsObject(Seq(
        "id" -> JsNumber(user.id),
        "firstName" -> JsString(user.firstName),
        "lastName" -> JsString(user.lastName),
        "email" -> Json.toJson(user.email)
      ))
    }
    

    And you'd use it like this:

    scala> User(1L, "Some", "Person", Some("[email protected]"))
    res0: User = User(1,Some,Person,Some([email protected]))
    
    scala> Json.toJson(res0)
    res1: play.api.libs.json.JsValue = {"id":1,"firstName":"Some","lastName":"Person","email":"[email protected]"}
    
    scala> res1.as[User]
    res2: User = User(1,Some,Person,Some([email protected]))
    

    See the documentation for more information.