How to represent a curly brace in regex replace using javascript

Question

I want to be able to do the following string replacement:

Input: 3^4
Output: 3^{4}

I have written the following regex expression to solve it:

outputString=outputString.replace(/\^(-?[1-9][0-9]*)/g,"\^"+"{"+"$1"+unescape('}'));

The output escapes the braces to be something like: 3^/{4/}

Can someone suggest a solution to this?

Answer 1

Try this regex:

'3^4'.replace(/\^(\d+)/, '^{$1}');  // -> 3^{4}