I have set up an automated deployment script (in shell script) for my web application.
It uses java, tomcat, maven and a postgres database.
The deployment script does this:
It's all working and it's pretty neat - but it needs a little improvement. You see, even though it exits with a success message, sometimes the deploy was not successful because the web application did not start correctly.
I would like to refactor steps 5 and 6 so that after bring up the tomcat server, the deployment script would "tail -f" in the catalina.out file, looking either for a "server started successfully" message or an exception stack trace.
The tail -f output up to that point should be part of the output of the deployment script, and step 6 would "exit 0" or "exit 1" accordingly.
I know that should be possible, if not in shell script, maybe with python. The problem is I'm a java specialist - and by specialist I mean I suck at everything else :-)
Help please? :-)
I ended up implementing a solution using Python's subprocess.Popen, as suggested by @snies.
Here's what it looks like:
waitForIt.py
#! /usr/bin/env python
import subprocess
import sys
def main(argv):
filename = argv[1]
match=argv[2]
p = subprocess.Popen(['tail', '-n', '0', '-f', filename], stdout=subprocess.PIPE)
while True :
line = p.stdout.readline()
print line ,
if match in line :
break
p.terminate()
if __name__ == "__main__":
main(sys.argv)
tailUntil.sh
#!/bin/bash
set -e
filename=$1
match=$2
thisdir=$(dirname $0)
python $thisdir/waitForIt.py "$filename" "$match"
and then
startTomcat.sh
${TOMCAT_HOME}/bin/startup.sh
logDeploy.sh "Agora vamos dar um tail no catalina.out..."
util_tailUntil.sh "$TOMCAT_HOME/logs/catalina.out" 'INFO: Server startup in '
It doesn't do what I originally intended (it still exits with return code 0 even when there is a stacktrace - but that could be changed with a little bit more of Python magic), but all of tomcat's initialization log is part of the automated deploy out (and easily viewable on Jenkins' deploy job) - so that's good enough.