How to re-throw an exception

Question

In my onCreate() I set an UncaughtException handler as follows:

Thread.setDefaultUncaughtExceptionHandler(new Thread.UncaughtExceptionHandler() {
    @Override
    public void uncaughtException(Thread thread, Throwable throwable) {
       Log.e(getMethodName(2), "uncaughtException", throwable);
       android.os.Process.killProcess(android.os.Process.myPid());
    }
});

It works OK, but I would like to get back the system's default behavior of displaying the force-close dialog to the user.

If I try to replace the KillProcess() call with a throw throwable the compiler complains that I need to surround it with a try/catch.

If I surround it with a try/catch:

Thread.setDefaultUncaughtExceptionHandler(new Thread.UncaughtExceptionHandler() {
    @Override
    public void uncaughtException(Thread thread, Throwable throwable) {
        try {
            Log.e(getMethodName(2), "uncaughtException", throwable);
            throw throwable;
        }
        catch (Exception e) {           
        }
        finally {               
        }
    }
});

The compiler still complains that throw throwable needs to be surrounded with a try/catch.

How do I re-throw that throwable? Such that except for that informative Log.e() the system behaves exactly as before: As is I never set a default UncaughtException handler.

Answer 1

Try:

public class CustomExceptionHandler implements UncaughtExceptionHandler {

    private UncaughtExceptionHandler defaultUEH;

    public CustomExceptionHandler() {
        this.defaultUEH = Thread.getDefaultUncaughtExceptionHandler();
    }

    public void uncaughtException(Thread t, Throwable e) {
        Log.e("Tag", "uncaughtException", throwable);
        defaultUEH.uncaughtException(t, e);
    }
}

and then Thread.setDefaultUncaughtExceptionHandler(new CustomExceptionHandler());

Adapted from this answer.