Code:
catch (IOException e) {
LOGGER.error("IOException exception happened");
//now need throw again the same exception to be
//catched in the upper method
}
But when I try simply:
catch (IOException e) {
LOGGER.error("IOException exception happened");
//now need throw again the same exception to be
//catched in the upper method
throw e;
}
Eclipse supposes to me put "throw e" in try catch block. But this is nonsense. How fix this problem? Thanks.
Since IOException
is a checked exception, that method needs to be declared as throwing IOException
if you want it to propagate. For example:
void myMethod() throws IOException {
try {
//code
}
catch(IOException e) {
LOGGER.error("IOException exception happened");
throw e;
}
}