I have written a Windows service that I am needing to port over to Mono so it can be used on Mac / Linux platforms.
It makes use of the FirewallAPI.dll (I think that is the actual name...). The other names are NetFwTypeLb, NATUPNPLib and NETCONLib.
I have been Googling, trying to find a way to implement this on Mac / Linux platforms but I cannot find what I could use to do this.
Is this possible? And combining another question with this one: do Mac / Linux platforms allow services (I think otherwise called 'daemons') to be installed and ran easily?
Thanks, Madeline
Just for note, this is the current code I am using, I got it off of another StackOverflow question:
public class Firewall
{
public static INetFwMgr WinFirewallManager()
{
Type type = Type.GetTypeFromCLSID(
new Guid("{304CE942-6E39-40D8-943A-B913C40C9CD4}"));
return Activator.CreateInstance(type) as INetFwMgr;
}
public bool AuthorizeProgram(string title, string path,
NET_FW_SCOPE_ scope, NET_FW_IP_VERSION_ ipver)
{
Type type = Type.GetTypeFromProgID("HNetCfg.FwAuthorizedApplication");
INetFwAuthorizedApplication authapp = Activator.CreateInstance(type)
as INetFwAuthorizedApplication;
authapp.Name = title;
authapp.ProcessImageFileName = path;
authapp.Scope = scope;
authapp.IpVersion = ipver;
authapp.Enabled = true;
EventLog.WriteEntry("MachineVerification", authapp.Name + " " + authapp.Scope + " " + authapp.IpVersion);
INetFwMgr mgr = WinFirewallManager();
try
{
mgr.LocalPolicy.CurrentProfile.AuthorizedApplications.Add(authapp);
EventLog.WriteEntry("MachineVerification", authapp.Name + " " + authapp.Scope + " " + authapp.IpVersion);
}
catch (Exception ex)
{
EventLog.WriteEntry("MachineVerification", "MROW!" + ex.Message);
return false;
}
return true;
}
}
I forgot to answer this when I figured it all out!
On OS X, there is no need for making a firewall exception. OS X will ask the user to give your application permission to access the internet.
I am not sure about Linux though, but Mono coverage is a lot higher on Linux so I am sure someone has answered this question for Linux before.