I have a call to
long long a = sqrt(n/2);
Both a
and n
are long long
's but it won't let me compile because it says my use of sqrt()
is an ambiguous call. I don't see how it's possibly ambiguous here at all. How do I resolve this? I have the same problem with floor()
.
My includes
#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;
There are several overloads of sqrt()
and floor()
, there's no "best match" for a call to sqrt(long long)
according to the overload resolution rules. Just cast the argument to the appropriate type -- i.e.,
long long a = sqrt(static_cast<double>(n/2));