Cant seem to find the answer to this.
My code looks like this:
var new_img = '<img id="' + drag_id + '" rel="' + drop_id + '" class="' + gallery_link + ' drop_out" src="' + drag_src + '" />';
var drop_img = '<div id="' + ($(ui.draggable).attr("id")) + '" class="not-droppable" rel="' + drop_id + '">' + new_img + '</div>';
$(drop_img).hide().prependTo('li[id=' + drop_id + ']').fadeIn(2000);
When the div
with the image inside it is prepended to the LI
it adds style:display-block
to the div
. How do I make it so that the prepended div
does not add the style
element as the class
for this element is display: inline-block
?
I have tried setting the style
element on the div
tag above to display: inline-block
; however, this then gets changed to display: block
. If I try and set the CSS display: inline-block
in the stylesheet to !important
the div
, style
becomes display-none
.
Thanks.
$(drop_img)
.css('display','none')
.prependTo('li[id=' + drop_id + ']')
.fadeIn(2000);
.hide()
works on element that already in DOM.