How to return answer of three fourths of Booleans in java

Question

Hey guys I was wondering if there was any way to return a certain fraction of a bunch of booleans in java. Simply put I would like to find out if there is a way to create a method that when given four booleans if three of them are true it returns true but if less than three are true it returns false. I know this might be hard to understand and if you don't understand just post a comment saying so.

Answer 1

Weird question ... anyway, here's a possible solution for just 4 booleans:

public boolean booleanFraction(boolean a, boolean b, boolean c, boolean d) {
    int ia = a ? 1 : 0;
    int ib = b ? 1 : 0;
    int ic = c ? 1 : 0;
    int id = d ? 1 : 0;
    return ia + ib + ic + id == 3;
}

For a more general solution, here's a method that receives as parameters the number of booleans that need to be true for considering true the whole expression, and a greater than zero variable number of boolean values:

public static boolean booleanFraction(int number, boolean... bools) {
    int acc = 0;
    for (boolean b : bools)
        acc += b ? 1 : 0;
    return acc == number;
}

Call it like this, for the example in the question:

booleanFraction(3, true, true, true, false);
> true

booleanFraction(3, false, false, true, false);
> false