I have this program :
int r = 4;//number add to d
int n = 3;//number of 0 add after 25
BigDecimal d = BigDecimal.valueOf(0.0025);
finaly i want to generate number : 0.0025004
and this number is generated by:
add n
position after d
then my number was : 0.0025000
and finaly add 0.000004
to my number 4 is r
.
I know there are a several ways to do, but i want to avoid loop
and use a maximum fonctinnality of BigDecimal
try it:
int r = 4;// number add to d
int n = 3;// number of 0 add after 25
BigDecimal d = BigDecimal.valueOf(0.0025);
double f = r / Math.pow(10, d.scale() + n);
System.out.println(d.add(BigDecimal.valueOf(f)));
I hope this is useful