I have an image which I resize:
if((width != null) || (height != null))
{
try{
// Scale image on disk
BufferedImage originalImage = ImageIO.read(file);
int type = originalImage.getType() == 0 ? BufferedImage.TYPE_INT_ARGB
: originalImage.getType();
BufferedImage resizedImageJpg = resizeImage(originalImage, type, 200, 200);
ImageIO.write(resizedImageJpg, "jpg", file);
} catch(IOException e) {
System.out.println(e.getMessage());
}
}
This is how I resize the image:
private static BufferedImage resizeImage(BufferedImage originalImage, int type,
Integer imgWidth, Integer imgHeight)
{
var resizedImage = new BufferedImage(imgWidth, imgHeight, type);
Graphics2D g = resizedImage.createGraphics();
g.drawImage(originalImage, 0, 0, imgWidth, imgHeight, null);
g.dispose();
return resizedImage;
}
Now the problem is, I also need to maintain aspect ratio. That is, I need the new 200/200 image to contain the new image scaled. Something like this:
I tried some things but they didn't work out as expected. Any help is appreciated.
Here we go:
Dimension imgSize = new Dimension(500, 100);
Dimension boundary = new Dimension(200, 200);
Function to return the new size depending on the boundary:
public static Dimension getScaledDimension(Dimension imgSize, Dimension boundary) {
int original_width = imgSize.width;
int original_height = imgSize.height;
int bound_width = boundary.width;
int bound_height = boundary.height;
int new_width = original_width;
int new_height = original_height;
// first check if we need to scale width
if (original_width > bound_width) {
//scale width to fit
new_width = bound_width;
//scale height to maintain aspect ratio
new_height = (new_width * original_height) / original_width;
}
// then check if we need to scale even with the new height
if (new_height > bound_height) {
//scale height to fit instead
new_height = bound_height;
//scale width to maintain aspect ratio
new_width = (new_height * original_width) / original_height;
}
return new Dimension(new_width, new_height);
}
In case anyone also needs the image resizing code, here is a decent solution.
If you're unsure about the above solution, there are different ways to achieve the same result.