In my previous question, Open a file from a specific program from python, I found out how to use subprocess in order to open a program (Blender) — well, a specific .blend
file — from a specific file path with this code.
import os
import subprocess
path = os.getcwd()
os.system("cd path/")
subprocess.check_call(["open", "-a", os.path.join(path, "blender.app"),"Import_mhx.blend"])
With the help of a guy at a forum, I wanted to use relative paths inside the .blend
file, so I changed the code in this way (for Windows)
import os
import subprocess
# This should be the full path to your Blender executable.
blenderPath = "/cygdrive/c/Program Files/Blender Foundation/blender-2.62-release-windows32/blender.exe"
# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"
# This makes makes it so your script is currently based at "path1"
os.chdir(path1)
subprocess.check_call([blenderPath, "Import_mhx.blend"])
and for Mac,
import os
import subprocess
path = os.getcwd()
os.system("cd path/")
print (path)
# This should be the full path to your Blender executable.
blenderPath = path + "/blender.app/Contents/macos/blender"
# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"
# This makes makes it so your script is currently based at "path1"
os.chdir(path1)
subprocess.check_call([blenderPath, "Import_mhx.blend"])
Results:
Questions:
.blend
files?import os
import subprocess
blenderPath = "./blender.app/Contents/MacOS/blender"
path1 = "./"
os.chdir(path1)
subprocess.check_call([ blenderPath, "Animation.blend"])
Both blender opens perfectly and relative paths inside .blend file work ok:)