I am working on making an expression class:
template<typename T, typename U>
class expression
{
public:
expression(T vala, U valb, oper o){val1 = vala; val2 = valb; op = o;}
operator bool{return(val1 op val2);}
private:
T val1;
U val2;
oper op;
};
as you can see, this is somewhat pseudocode, because I need an operator class. My original thought was to create an array of all possible operators, and then convert it through a string, but that wouldn't work because of the sheer number of operators, and how to convert it to a string except through a two dimensional array, where n[0][0] has the first operator, and n[0][1] has that operators string.
Does anybody have any suggestions to adding an operator value to my expression class?
Maybe a function pointer. Instead of ...
operator bool{return(val1 op val2);}
... code it as ...
operator bool{return op(val1, val2);}
... in which case op
can be a pointer to a (any) function which takes two parameters and which returns bool.
template<typename T, typename U>
class expression
{
public:
//define pointer-to-function type
typedef bool *oper(const T& val1, const U& val2);
... etc ...