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pythonfloating-pointexponent

Number of digits in exponent

Is it possible to set the number of digits to be used for printing the exponent of a floating-point number? I want to set it to 3.

Currently,

f = 0.0000870927939438012
>>> "%.14e"%f
'8.70927939438012e-05'
>>> "%0.14e"%f
'8.709279e-005'

What I want to print is: '8.70927939438012e-005'

Solution

  • There is a no way to control that, best way is to write a function for this e.g.

    def eformat(f, prec, exp_digits):
    s = "%.*e"%(prec, f)
    mantissa, exp = s.split('e')
    # add 1 to digits as 1 is taken by sign +/-
    return "%se%+0*d"%(mantissa, exp_digits+1, int(exp))

print(eformat(0.0000870927939438012, 14, 3))
print(eformat(1.0000870927939438012e5, 14, 3))
print(eformat(1.1e123, 4, 4))
print(eformat(1.1e-123, 4, 4))

    Output:

    8.70927939438012e-005
1.00008709279394e+005
1.1000e+0123
1.1000e-0123