Consider the following code:
#include <iostream>
#include <vector>
#include <boost/numeric/ublas/vector.hpp>
#include <boost/numeric/ublas/io.hpp>
int main()
{
namespace ublas = boost::numeric::ublas;
double d = M_PI;
unsigned u = d;
std::cout << "d = " << d << std::endl;
std::cout << "u = " << u << std::endl;
ublas::bounded_vector<double,3> dVec = ublas::scalar_vector<double>(3,M_PI);
ublas::bounded_vector<unsigned,3> uVec = dVec; // type conversion!
std::cout << "dVec = " << dVec << std::endl;
std::cout << "uVec = " << uVec << std::endl;
return 0;
}
When I compile this using g++ (version 4.6.1) with the following options:
g++ -g3 -Wall -Wextra -ansi -pedantic -Wconversion -std=c++0x test.cpp -o test
I get the following warnings:
test.cpp: In function ‘int main()’:
test.cpp:11:22: warning: conversion to ‘unsigned int’ from ‘double’ may alter its value [-Wconversion]
When I run the program I get:
$ ./test
d = 3.14159
u = 3
dVec = [3](3.14159,3.14159,3.14159)
uVec = [3](3,3,3)
The compiler produced a warning for the conversion of the scalars but there was no warning for the ublas conversion, is there a way of having the compiler write a warning in that case? It looks like -Wconversion
or any of the other options don't do this.
Why should any compiler warn on this?
The authors of ublas::bounded_vector<T,N>
must have defined a conversion from ublas::bounded_vector<U,N>
, otherwise it would not be possible at all. And if there is such function/constructor, there is no reason for the compiler to warn you when you use it.