Mixing Out and Named Parameters in C#: Why Does Out Parameter Need to be Named As Well?

Question

Short Version: A named argument following an out argument gives a compiler error, but I cannot find any support for this behaviour in the language specification.

Long Version:

I'm using the Enum.TryParse<TEnum> three parameter overload, but I would prefer to name the ignoreCase parameter to make my code clearer, a call like:

MyEnum res;
b = Enum.TryParse<MyEnum>(inputString, true, out res);

leaves the meaning of the boolean unclear (unless this method is known¹). Hence I would like to use:

b = Enum.TryParse<MyEnum>(inputString, out res, ignoreCase: true);

However the compiler reports this as an error:

Named argument 'ignoreCase' specifies a parameter for which a positional argument has already been given

and the IDE highlights the ignoreCase parameter. VS2010 targeting .NET 4, and VS11 Beta targeting either 4 or 4.5 all give the same result. In all cases naming the out parameter removes the error.

b = Enum.TryParse<MyEnum>(inputString, result: out res, ignoreCase: true);

I've tried this across a number of different methods (including avoiding generics)², both from the framework and in my assembly: always the same result: an out parameter followed by a named parameter gives an error.

I can see no reason for this error, and §7.5.1 Argument Lists of the C# Language Specification: Version 4.0 does not seem to provide any reason why an out followed by a named parameter should give an error. The text of the error seems to support an interpretation as a bug: there is no positional argument which could be a valid match for ignoreCase.

Is my reading of the specification wrong? Or is this a compiler bug?

C# 7.2 Update

This restriction on all named arguments have to follow positional arguments when calling was lifted with C# 7.2.

See https://learn.microsoft.com/en-gb/dotnet/csharp/whats-new/csharp-7-2#non-trailing-named-arguments.

---

¹ Hence the advice in the Framework Design Guidelines to prefer enum parameters.

² Eg: given:

private static void TestMethod(int one, float two, out string three) {
  three = "3333";
}

this this call also gives the same error on the named parameter unless the out parameter is also named:

TestMethod(1, out aString, two: 1.0f);

Answer 1

Named parameters do not allow you to "skip" positional arguments.

Your code is parsed as passing the first two arguments—value and ignoreCase, then passing ignoreCase again.
It has nothing to do with the outness of the parameter.

You can fix it by passing the last parameter as named too.