I have a layout page with the following
_app.cshtml
<div id="top_right">
@{ Html.Partial("_LogOnPartial"); }
</div>
The log on partial contains
_LogOnPartial.cshtml
@{
Layout = null;
}
@if (Request.IsAuthenticated)
{
Html.RenderAction("Details", "Account");
}
else
{
Html.RenderAction("LogOn", "Account");
}
and the render action method im expecting to see is
AccountController.cs
public class Account
{
public PartialViewResult LogOn()
{
return PartialView();
}
}
the Logon partial view that would be returned by Account/LogOn is
LogOn.cshtml
@model Presentation.Models.LogOnModel
<div id="login">
@Html.ValidationSummary()
<h2>Start by Loggin in</h2>
@using (Html.BeginForm("LogOn", "Account"))
{
@Html.Hidden("returnUrl", Request.Url.PathAndQuery)
<table width="100%" border="0" cellspacing="0" cellpadding="5">
<tr>
<td>
<span class="bluey">Username:</span><br />
@Html.TextBoxFor(m => m.UserName, new {tabindex = "1", Class = "field"})
@Html.ValidationMessageFor(m => m.UserName, "*")
</td>
<td>
<span class="bluey">Password:</span><br />
@Html.TextBoxFor(m => m.Password, new {tabindex = "2", Class = "field"})
@Html.ValidationMessageFor(m => m.Password, "*")
</td>
</tr>
<tr>
<td>
<input name="login" type="submit" value="Submit" class="input_btn" tabindex="3" />
</td>
<td>@Html.CheckBoxFor(m => m.RememberMe) @Html.LabelFor(m => m.RememberMe) <span class="bluey"> | </span> @Html.ActionLink("Forgot Password?", "Password", "User")></td>
</tr>
</table>
}
</div>
I have traced the flow through and I can see it is hitting the
Html.RenderAction("LogOn", "Account")
and returning the partial view from there however when I view the page none of the html of the partial view (LogOn.cshtml) is rendered, it isn't even present in the source.
Am I missing something fundamental here, is there a better way to achieve this?
You have a code block which will be returning the partial rather than outputting it, change:
<div id="top_right">
@{ Html.Partial("_LogOnPartial"); }
</div>
to:
<div id="top_right">
@Html.Partial("_LogOnPartial");
</div>
Alternatively, use Html.RenderPartial
to output it directly.