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c++clinuxunixpath

How do I find the location of the executable in C?


Is there a way in C/C++ to find the location (full path) of the current executed program?

(The problem with argv[0] is that it does not give the full path.)


Solution

  • To summarize:

    • On Unixes with /proc really straight and realiable way is to:

      • readlink("/proc/self/exe", buf, bufsize) (Linux)

      • readlink("/proc/curproc/file", buf, bufsize) (FreeBSD)

      • readlink("/proc/self/path/a.out", buf, bufsize) (Solaris)

    • On Unixes without /proc (i.e. if above fails):

      • If argv[0] starts with "/" (absolute path) this is the path.

      • Otherwise if argv[0] contains "/" (relative path) append it to cwd (assuming it hasn't been changed yet).

      • Otherwise search directories in $PATH for executable argv[0].

      Afterwards it may be reasonable to check whether the executable isn't actually a symlink. If it is resolve it relative to the symlink directory.

      This step is not necessary in /proc method (at least for Linux). There the proc symlink points directly to executable.

      Note that it is up to the calling process to set argv[0] correctly. It is right most of the times however there are occasions when the calling process cannot be trusted (ex. setuid executable).

    • On Windows: use GetModuleFileName(NULL, buf, bufsize)