Make a running process the active Window

Question

I have three Microsoft Access databases. I want to be able to switch between these programmatically. I have a void method which accepts a string parameter called dbName (my database name).

public void SwitchDatabase(string dbName)
{

}

I know what the MainWindowTitle of my Access Database is and each database has a different MainWindowTitle so I can create an array of the Process class and make this equal so System.Diagnostics.Process.GetProcesses(). I can then loop through my running processes until I find the one where the ProcessName is MSACCESS and the MainWindowTitle is correct like so:

Process[] processList = Process.GetProcesses();

foreach (Process theProcess in processList)
{
    string processName = theProcess.ProcessName;
    string mainWindowTitle = theProcess.MainWindowTitle;
}

Once I find this, I can then grab the Process ID, and now I want to make this process my active window. How do I do this?

Answer 1

Try this:

[DllImport("user32.dll", CharSet=CharSet.Auto,ExactSpelling=true)]
public static extern IntPtr SetFocus(HandleRef hWnd);


[TestMethod]
public void PlayAround()
{
    Process[] processList = Process.GetProcesses();

    foreach (Process theProcess in processList)
    {
        string processName = theProcess.ProcessName;
        string mainWindowTitle = theProcess.MainWindowTitle;
        SetFocus(new HandleRef(null, theProcess.MainWindowHandle));
    }

}