I'll describe what I am trying to achieve:
I am passing down to a SP an xml with name value pairs that I put into a table variable, let's say @nameValuePairs
.
I need to retrieve a list of IDs for expressions (a table) with those exact match of name-value pairs (attributes, another table) associated.
This is my schema:
Expressions table --> (expressionId, attributeId)
Attributes table --> (attributeId, attributeName, attributeValue)
After trying complicated stuff with dynamic SQL and evil cursors (which works but it's painfully slow) this is what I've got now:
--do the magic plz!
-- retrieve number of name-value pairs
SET @noOfAttributes = select count(*) from @nameValuePairs
select distinct
e.expressionId, a.attributeName, a.attributeValue
into
#temp
from
expressions e
join
attributes a
on
e.attributeId = a.attributeId
join --> this join does the filtering
@nameValuePairs nvp
on
a.attributeName = nvp.name and a.attributeValue = nvp.value
group by
e.expressionId, a.attributeName, a.attributeValue
-- now select the IDs I need
-- since I did a select distinct above if the number of matches
-- for a given ID is the same as noOfAttributes then BINGO!
select distinct
expressionId
from
#temp
group by expressionId
having count(*) = @noOfAttributes
Can people please review and see if they can spot any problems? Is there a better way of doing this?
Any help appreciated!
I belive that this would satisfy the requirement you're trying to meet. I'm not sure how much prettier it is, but it should work and wouldn't require a temp table:
SET @noOfAttributes = select count(*) from @nameValuePairs
SELECT e.expressionid
FROM expression e
LEFT JOIN (
SELECT attributeid
FROM attributes a
JOIN @nameValuePairs nvp ON nvp.name = a.Name AND nvp.Value = a.value
) t ON t.attributeid = e.attributeid
GROUP BY e.expressionid
HAVING SUM(CASE WHEN t.attributeid IS NULL THEN (@noOfAttributes + 1) ELSE 1 END) = @noOfAttributes
EDIT: After doing some more evaluation, I found an issue where certain expressions would be included that shouldn't have been. I've modified my query to take that in to account.