Search code examples
z3

Incremental calls to Z3 on UFBV with and without push calls


I am running Z3 on UFBV queries. Currently the query contains 2 calls check-sat. If I put push 1 just after check-sat, Z3 solves the query in 30sec. If I don't put any push 1 at all, thus have two calls check-sat without any push 1 between them, then Z3 solves it in 200sec. Interesting. Any specific reasons or just a coincidence?


Solution

  • Z3 3.x has a "strategy specification language" based on tactics and tacticals. I'm not "advertising" that yet because it is working in progress. The basic idea is described in this slide deck. We have a different built-in strategy for each logic. The strategies usually do not support incremental solving, because they may apply transformations that use a "closed-world" assumption. Example, we have transformations that map 0-1 linear integer arithmetic into SAT. Whenever Z3 detects that the user "wants" incremental solving (e.g., multiple check-sat commands, push&pop commands), it switches to a general purpose solver. In future versions, we will provide more features for controlling Z3 behavior.

    BTW, if you have two consecutive (check-sat) (check-sat) commands, Z3 not necessarily enters in incremental mode. It will enter only if there is an assert or push command between the two calls.

    Now, suppose your query is of the form: (check-sat) <assertions> (check-sat), and your second query is of the form (check-sat) <assertions> (push) (check-sat). In both cases, Z3 will be in incremental mode in the second (check-sat). However, the behavior is still not the same. The incremental solver "compiles" the asserted formulas to an internal format, and its behavior is affected if a push command has been executed. For example, it will use a more efficient encoding of binary clauses only if there is no user scope. By user scope, I mean, the number of push commands - number of pop commands. It does that because the data-structure used in the more efficient encoding does not have an efficient undo/inverse operation.