I am trying to use both mysqli_real_escape_string
and trim
together before making a MySQL INSERT
query. My code is as follows:
<?php
$fname = mysqli_real_escape_string($dbc, trim($_POST['fname']));
$sname = mysqli_real_escape_string($dbc, trim($_POST['sname']));
$occ = mysqli_real_escape_string($dbc, trim($_POST['occ']));
$twitter = mysqli_real_escape_string($dbc, trim($_POST['twitter']));
$email = mysqli_real_escape_string($dbc, trim($_POST['email']));
$skype = mysqli_real_escape_string($dbc, trim($_POST['skype']));
$topic1 = mysqli_real_escape_string($dbc, trim($_POST['topic1']));
$topic2 = mysqli_real_escape_string($dbc, trim($_POST['topic2']));
$topic3 = mysqli_real_escape_string($dbc, trim($_POST['topic3']));
$avoid1 = mysqli_real_escape_string($dbc, trim($_POST['avoid1']));
$avoid2 = mysqli_real_escape_string($dbc, trim($_POST['avoid2']));
$avoid3 = mysqli_real_escape_string($dbc, trim($_POST['avoid3']));
$cr = mysqli_real_escape_string($dbc, trim($_POST['cr']));
if ((!empty($fname)) && (!empty($sname)) && (!empty($email)) && (!empty($topic1))) {
$dbc = mysqli_connect('host', 'user', 'password', 'database') or die('Error connecting to MySQL server');
$query = "INSERT INTO initial_details (fname, sname, occ, twitter, email, skype, topic1, topic2, topic3, avoid1, avoid2, avoid3, cr) VALUES ('$fname', '$sname', '$occ', '$twitter', '$email', '$skype', '$topic1', '$topic2', '$topic3', '$avoid1', '$avoid2', '$avoid3', '$cr')";
$result = mysqli_query($dbc, $query);
if (!$result) {
mysqli_close($dbc);
echo 'Duplicate';
} else {
mysqli_close($dbc);
echo 'Success - entry added';
}
} else {
echo 'Error';
}
?>
Using the code as above I get the 'Error' message, however if I remove mysqli_real_escape_string()
and just use trim
I am able to insert my entry successfully.
Why am I not able to use mysqli_real_escape_string()
in this scenario?
$dbc = mysqli_connect
must precede all the mysqli_real_escape_string
calls to make it work. This is because you need an active mysqli connection to use that function.