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vhdl

shift a std_logic_vector of n bit to right or left

I have a vector signal tmp : std_logic_vector(15 downto 0)

I have to shift it to left or right of n bit. how can I realize this operation. I thought to concatenation operation but I didn't know how use it.

Solution

  • Use the ieee.numeric_std library, and the appropriate vector type for the numbers you are working on (unsigned or signed).

    Then the operators are `sla`/`sra` for arithmetic shifts (ie fill with sign bit on right shifts and lsb on left shifts) and `sll`/`srl` for logical shifts (ie fill with '0's).

    You pass a parameter to the operator to define the number of bits to shift:

    A <= B srl 2; -- logical shift right 2 bits
    --- Update: --- I have no idea what I was writing above (thanks to Val for pointing that out!)

    Of course the correct way to shift signed and unsigned types is with the shift_left and shift_right functions defined in ieee.numeric_std.

    The shift and rotate operators sll, ror etc are for vectors of boolean, bit or std_ulogic, and can have interestingly unexpected behaviour in that the arithmetic shifts duplicate the end-bit even when shifting left.

    And much more history can be found here:

    http://jdebp.eu./FGA/bit-shifts-in-vhdl.html

    However, the answer to the original question is still

    sig <= tmp sll number_of_bits;