I have a factor in R, with an NA level.
set.seed(1)
x <- sample(c(1, 2, NA), 25, replace=TRUE)
x <- factor(x, exclude = NULL)
> x
[1] 1 2 2 <NA> 1 <NA> <NA> 2 2 1 1
[12] 1 <NA> 2 <NA> 2 <NA> <NA> 2 <NA> <NA> 1
[23] 2 1 1
Levels: 1 2 <NA>
How do I subset that factor by the <NA>
level? Both methods I tried did not work.
> x[is.na(x)]
factor(0)
Levels: 1 2 <NA>
> x[x=='<NA>']
factor(0)
Levels: 1 2 <NA>
Surprising to me that your attempts to do this didn't work, but this seems to:
x[is.na(levels(x)[x])]
I got there by looking at str(x)
and seeing that it is the levels that are NA
, not the underlying codes:
str(x)
Factor w/ 3 levels "1","2",NA: 1 2 2 3 1 3 3 2 2 1 ...