Doing something like this:
from zipfile import ZipFile
#open zip file
zipfile = ZipFile('Photo.zip')
#iterate zip contents
for zipinfo in zipfile.filelist:
#do something
filepath, filename = path.split(zipinfo.filename)
How do I know if zipinfo
is a file or a directory?
Probably this is the right way:
is_dir = lambda zipinfo: zipinfo.filename.endswith('/')