I have the following sum:
sum((R[i]-(a*X[i]+b)*t + 1/2*(c*X[i]+d)^2*t)^2/((c*X[i]+d)^2*t), i, 1, N);
which I want to differenciate wrt. a:
diff(%, a);
but Maxima (wxMaxima to be precise) just prints d/da . Can I make it actually differentiate the sum (so because N is finite is should differentiate every element in the sum separately)?
If I set N to some constant, e.g.:
sum((R[i]-(a*X[i]+b)*t + 1/2*(c*X[i]+d)^2*t)^2/((c*X[i]+d)^2*t), i, 1, 100);
then I get explicit sum of 100 elements (takes about 2 pages), and then differentiation works (but again I get 2 pages instead of a small sum). Can I get this result displayed as a sum?
Which version of Maxima do you use ?
Here is my session of Maxima with you equation differentiated wrt.a and than substituted to N=100.
~$ maxima
Maxima 5.24.0 http://maxima.sourceforge.net
using Lisp SBCL 1.0.51
Distributed under the GNU Public License. See the file COPYING.
Dedicated to the memory of William Schelter.
The function bug_report() provides bug reporting information.
(%i1) sum((R[i]-(a*X[i]+b)*t + 1/2*(c*X[i]+d)^2*t)^2/((c*X[i]+d)^2*t), i, 1, N);
2
(c X + d) t
N i 2
==== (------------- - (a X + b) t + R )
\ 2 i i
> ------------------------------------
/ 2
==== (c X + d)
i = 1 i
(%o1) ------------------------------------------
t
(%i2) diff(%, a);
2
(c X + d) t
N i
==== X (------------- - (a X + b) t + R )
\ i 2 i i
(%o2) - 2 > --------------------------------------
/ 2
==== (c X + d)
i = 1 i
(%i3) %, N=100;
2
(c X + d) t
100 i
==== X (------------- - (a X + b) t + R )
\ i 2 i i
(%o3) - 2 > --------------------------------------
/ 2
==== (c X + d)
i = 1 i