#include<iostream>
template<class T>
struct Foo
{
T v_;
Foo(T&& v):v_(std::forward<T>(v))
{
std::cout << "building Foo..\n";
}
};
int main()
{
int v;
Foo<int> foo(v);
std::cin.ignore();
}
visual c++ 2010 output :
error C2664:
'Foo<T>::Foo(T &&)'
: cannot convert parameter 1 from'int'
to'int &&'
Is it normal that I can't bind a lvalue to a rvalue reference ?
EDIT:
same thing for a function :
void f(int && v)
{
}
int v;
f(v); //won't compile
I'm a little bit confused because I think std::forward is usefull to detect if a method is called with a lvalue or a rvalue reference. But it seems that we can't bind any lvalue into rvalue reference... at least without template parameter but I don't understand it very well
It's normal that calling a move constructor requires an r-value, not an l-value, since an l-value could be named after the move constructor runs, and using a moved-from value would evoke unintended behavior.