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bandwidthmegabyte

Converting from bandwidth to traffic gives different results depending on operators position?

This must be a stupid question, but nevertheless I find it curious:

Say I have a steady download of 128Kbps.

How much disk space is going to be consumed after a hour in Megabytes?

128 x 60 x 60 / 8 / 1024 = 56.25 MB

But

128 x 60 x 60 / 1000 /8 = 57.6 MB

So what is the correct way to calculate this?

Thanks!

Solution

  • Ok, I found out an official explanation from Symantec on the matter: http://seer.entsupport.symantec.com/docs/274171.htm

    It seems the idea is to convert from bits to bytes as early as possible in calculation, and then the usual 1024 division comes in place.

    I just hope it's a standard procedure, and not Symantec imposed one :).