Why is the dereference operator (*) also used to declare a pointer?

Question

I'm not sure if this is a proper programming question, but it's something that has always bothered me, and I wonder if I'm the only one.

When initially learning C++, I understood the concept of references, but pointers had me confused. Why, you ask? Because of how you declare a pointer.

Consider the following:

void foo(int* bar)
{
}


int main()
{
    int x = 5;
    int* y = NULL;

    y = &x;
    *y = 15;     
    foo(y);

}

The function foo(int*) takes an int pointer as parameter. Since I've declared y as int pointer, I can pass y to foo, but when first learning C++ I associated the * symbol with dereferencing, as such I figured a dereferenced int needed to be passed. I would try to pass *y into foo, which obviously doesn't work.

Wouldn't it have been easier to have a separate operator for declaring a pointer? (or for dereferencing). For example:

void test(int@ x)
{
}

Answer 1

In The Development of the C Language, Dennis Ritchie explains his reasoning thusly:

The second innovation that most clearly distinguishes C from its predecessors is this fuller type structure and especially its expression in the syntax of declarations... given an object of any type, it should be possible to describe a new object that gathers several into an array, yields it from a function, or is a pointer to it.... [This] led to a declaration syntax for names mirroring that of the expression syntax in which the names typically appear. Thus,

int i, *pi, **ppi; declare an integer, a pointer to an integer, a pointer to a pointer to an integer. The syntax of these declarations reflects the observation that i, *pi, and **ppi all yield an int type when used in an expression.

Similarly, int f(), *f(), (*f)(); declare a function returning an integer, a function returning a pointer to an integer, a pointer to a function returning an integer. int *api[10], (*pai)[10]; declare an array of pointers to integers, and a pointer to an array of integers.

In all these cases the declaration of a variable resembles its usage in an expression whose type is the one named at the head of the declaration.

An accident of syntax contributed to the perceived complexity of the language. The indirection operator, spelled * in C, is syntactically a unary prefix operator, just as in BCPL and B. This works well in simple expressions, but in more complex cases, parentheses are required to direct the parsing. For example, to distinguish indirection through the value returned by a function from calling a function designated by a pointer, one writes *fp() and (*pf)() respectively. The style used in expressions carries through to declarations, so the names might be declared

int *fp(); int (*pf)();

In more ornate but still realistic cases, things become worse: int *(*pfp)(); is a pointer to a function returning a pointer to an integer.

There are two effects occurring. Most important, C has a relatively rich set of ways of describing types (compared, say, with Pascal). Declarations in languages as expressive as C—Algol 68, for example—describe objects equally hard to understand, simply because the objects themselves are complex. A second effect owes to details of the syntax. Declarations in C must be read in an `inside-out' style that many find difficult to grasp. Sethi [Sethi 81] observed that many of the nested declarations and expressions would become simpler if the indirection operator had been taken as a postfix operator instead of prefix, but by then it was too late to change.