Get text in quotes

is there is some function that can take just text inside the quotes from the variable?
Just like:

$text = 'I am "pro"';
echo just_text_in_quotes($text);

I know that this function doesn't exist.. but I need something like that. I was thinking about fnmatch("*",$text) But this cant Echo just that text, It's just for check. Can you please help me? Thank you.

Solution

This function will return the first matched text between quotes (possibly an empty string).

function just_text_in_quotes($str) {
   preg_match('/"(.*?)"/', $str, $matches);
   return isset($matches[1]) ? $matches[1] : FALSE;
}

You could modify it to return an array of all matches, but in your example you use it within the context of echoing its returned value. Had it returned an array, all you would get is Array.

You may be better off writing a more generic function that can handle multiple occurrences and a custom delimiter.

function get_delimited($str, $delimiter='"') {
    $escapedDelimiter = preg_quote($delimiter, '/');
    if (preg_match_all('/' . $escapedDelimiter . '(.*?)' . $escapedDelimiter . '/s', $str, $matches)) {
        return $matches[1];
    }
}

This will return null if no matches were found.