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c#xmllinq-to-xmlxelement

XElement => Add children nodes at run time


So let's assume this is what i want to achieve:

<root>
  <name>AAAA</name>
  <last>BBBB</last>
  <children>
     <child>
        <name>XXX</name>
        <last>TTT</last>
     </child>
     <child>
        <name>OOO</name>
        <last>PPP</last>
     </child>
   </children>
</root>

Not sure if using XElement is the simplest way
but this is what I have so far:

 XElement x = new XElement("root",
                  new XElement("name", "AAA"),
                  new XElement("last", "BBB"));

Now I have to add the "children" based on some data i have.
There could be 1,2,3,4 ...

so I need to iterate thru my list to get every single child

foreach (Children c in family)
{
    x.Add(new XElement("child", 
              new XElement("name", "XXX"),
              new XElement("last", "TTT")); 
} 

PROBLEM:

Doing this way I will be missing the "CHILDREN Parent node". If I just add it before the foreach, it will be rendered as a closed node

<children/>

and that's NOT what we want.

QUESTION:

How can I add to the 1st part a parent node and as many as my list has?


Solution

  • Try this:

    var x = new XElement("root",
                 new XElement("name", "AAA"),
                 new XElement("last", "BBB"),
                 new XElement("children",
                     from c in family
                     select new XElement("child",
                                 new XElement("name", "XXX"),
                                 new XElement("last", "TTT")
                            )
                 )
            );