I'm trying to define some subroutines that have calls to printf in them. A very trivial example is as follows:
extern printf
LINUX equ 80H
EXIT equ 60
section .data
intfmt: db "%ld", 10, 0
segment .text
global main
main:
call os_return ; return to operating system
os_return:
mov rax, EXIT ; Linux system call 60 i.e. exit ()
mov rdi, 0 ; Error code 0 i.e. no errors
int LINUX ; Interrupt Linux kernel
test:
push rdi
push rsi
mov rsi, 10
mov rdi, intfmt
xor rax, rax
call printf
pop rdi
pop rsi
ret
Here test just has a call to printf that outputs the number 10 to the screen. I would not expect this to get called as I have no call to it.
However when compiling and running:
nasm -f elf64 test.asm
gcc -m64 -o test test.o
I get the output:
10
10
I'm totally baffled and wondered if someone could explain why this is happening?
int 80H
invokes the 32-bit system call interface, which a) uses the 32-bit system call numbers and b) is intended for use by 32-bit code, not 64-bit code. Your code is actually performing a umask
system call with random parameters.
For a 64-bit system call, use the syscall
instruction instead:
...
os_return:
mov rax, EXIT ; Linux system call 60 i.e. exit ()
mov rdi, 0 ; Error code 0 i.e. no errors
syscall ; Interrupt Linux kernel
...