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pythondecorator

Python convert args to kwargs


I am writing a decorator that needs to call other functions prior to call of the function that it is decorating. The decorated function may have positional arguments, but the functions the decorator will call can only accept keyword arguments. Does anyone have a handy way of converting positional arguments into keyword arguments?

I know that I can get a list of the variable names of the decorated function:

>>> def a(one, two=2):
...    pass

>>> a.func_code.co_varnames
('one', 'two')

But I can't figure out how to tell what was passed in positionally and what was as keyword.

My decorator looks like this:

class mydec(object):
    def __init__(self, f, *args, **kwargs):
        self.f = f

    def __call__(self, *args, **kwargs):
        hozer(**kwargs)
        self.f(*args, **kwargs)

Is there a way other than just comparing kwargs and co_varnames, adding to kwargs anything not in there, and hoping for the best?


Solution

  • Note - co_varnames will include local variables as well as keywords. This probably won't matter, as zip truncates the shorter sequence, but may result in confusing error messages if you pass the wrong number of args.

    You can avoid this with func_code.co_varnames[:func_code.co_argcount], but better is to use the inspect module. ie:

    import inspect
    argnames, varargs, kwargs, defaults = inspect.getargspec(func)
    

    You may also want to handle the case where the function defines **kwargs or *args (even if just to raise an exception when used with the decorator). If these are set, the second and third result from getargspec will return their variable name, otherwise they will be None.