Python UUID badly formed hexadecimal string

Question

Trying to generate a UUID based on an 6.6 XY coordinate pair and the date. However I am giving the function a 'badly formed hexadecimal UUID string'. Python noob plz help.

def LeID(Xv,Yv,Dv):
    import uuid
    import string
    import arcpy
    X_val = "%.6f" % Xv
    Y_val  = "%.6f" % Yv
    date = Dv
    xarr = string.split(X_val, '.')
    yarr = string.split(Y_val, '.')
    date = string.split(date , '/')
    val =  str(xarr[0] + xarr[1] + yarr[0] + yarr[1] + date[0]  + date[1] + date[2] )
    return '{' + str(uuid.UUID(val).time_low()) + '}'

Answer 1

It won't work the way you think.

There are several types of UUID: based on time (UUID1), randomly (UUID4) or based on another UUID plus data, put together via MD5 (UUID3) or SHA1 (UUID5).

So you would take one previously defined UUID, maybe UUID('f82aa75f-56a8-442b-89d2-eb7aaae6f9c3'), as a namespace and derive all from this.

def LeID(Xv,Yv,Dv):
    import uuid
    import string
    import arcpy
    MyNS = uuid.UUID('f82aa75f-56a8-442b-89d2-eb7aaae6f9c3')
    X_val = "%.6f" % Xv
    Y_val  = "%.6f" % Yv
    date = Dv
    xarr = string.split(X_val, '.')
    yarr = string.split(Y_val, '.')
    date = string.split(date , '/')
    val =  str(xarr[0] + xarr[1] + yarr[0] + yarr[1] + date[0]  + date[1] + date[2] )
    print MyNS, repr(val) # for debugging
    return '{' + str(uuid.uuid5(MyNS, val)) + '}'