How to write LEFT OUTER JOIN on the same table in jOOQ?

Question

how to write following SQL using jOOQ?

SELECT *
FROM food_db_schema.tblCategory AS t1
LEFT OUTER JOIN food_db_schema.tblCategory AS t2 ON t1.category_id = t2.parent_id
WHERE t2.parent_id IS NULL
AND t1.heartbeat = "ALIVE";

database is mySQL

Answer 1

Maybe

SELECT *
FROM food_db_schema.tblCategory AS t1
WHERE t1.category_id IS NULL
AND t1.heartbeat = "ALIVE";

, but are you sure t2.parent_id is both supposed to be NULL and equal to t1.category_id?

EDIT:

Then something like

Table<TblCategoryRecord> t1 = TBLCATEGORY.as("t1");
Table<TblCategoryRecord> t2 = TBLCATEGORY.as("t2");

Field<Integer> t1CategoryId = t1.getField(TblCategory.CATEGORY_ID);
Field<String> t1Heartbeat = t1.getField(TblCategory.HEARTBEAT);
Field<Integer> t2ParentId = t2.getField(TblCategory.PARENT_ID);

Record record = create.select().from(t1)
      .leftOuterJoin(t2).on(t1CategoryId.equal(t2ParentId))
      .where(t2ParentId.isNull())
      .and(t1Heartbeat.equal("ALIVE"));

depending on what the generated classes, properties and meta-model objects are called.