Push UIWebView as detail view (table)

Question

I want to create a app, where I'll have say 10 table rows (list view) and each would have a detail view. Now for each detail view, I want to show 10 different remote htmls (in UIWebView)?

How do I do this? Should I use array to store the 10 URLs? How do I pass the URL from list to detail view?

Just to add: I also want to show an iAd on the detail view. So hope that can be easily integrated.

Answer 1

You can create a WebViewController that will act as the "detail view". Add a new UIViewController subclass to your project and just add a UIWebView and an ADBannerView to your nib file. Make an outlet for your webView and you should be good to go. From your list view, you can create a new detailViewController and load your row-specific url to the webView:

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
    NSString* url = [[dataArray objectAtIndex:indexPath.row] objectForKey:@"url"];
    if (![url isEqualToString:@""]) {
        WebViewController* detailViewController = [[WebViewController alloc] initWithNibName:@"WebViewController" bundle:nil];
        [self.navigationController pushViewController:detailViewController animated:YES];
        [detailViewController.webView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:url]]];
        [detailViewController release];
    }
}

This is a quick way to do that - you could create a custom -init method that accepts a url if you want. You should also use the methods of the UIWebViewDelegate in order to show some loading feedback/error message regarding the webView:

@interface WebViewController : UIViewController <UIWebViewDelegate> {
    IBOutlet UIWebView* webView;
}