If I choose a zip file and right click "extract here" a folder with the zip filename is created and the entire content of the zip file is extracted into it.
However, I would like to convert several zip files via shell. But when I do
unzip filename.zip
the folder "filename" is not created but all the files are extracted into the current directory.
I have looked at the parameters but there is no such parameter. I also tried
for zipfile in \*.zip; do mkdir $zipfile; unzip $zipfile -d $zipfile/; done
but the .zip extension of the 2. $zipfile and 4. $zipfile have to be removed with sed.
If I do
for zipfile in \*.zip; do mkdir sed 's/\.zip//i' $zipfile; unzip $zipfile -d sed 's/\.zip//i' $zipfile/; done
it is not working.
How do I replace the .zip extension of $zipfile properly?
Is there an easier way than a shell script?
"extract here" is merely a feature of whatever unzip wrapper you are using. unzip will only extract what actually is in the archive. There is probably no simpler way than a shell script. But sed, awk etc. are not needed for this if you have a POSIX-compliant shell:
for f in *.zip; do unzip -d "${f%*.zip}" "$f"; done
(You MUST NOT escape the * or pathname expansion will not take place.) Be aware that if the ZIP archive contains a directory, such as with Eclipse archives (which always contain eclipse/), you would end up with ./eclipse*/eclipse/eclipse.ini in any case. Add echo before unzip for a dry run.