I wrote the follwing function:
let str2lst str =
let rec f s acc =
match s with
| "" -> acc
| _ -> f (s.Substring 1) (s.[0]::acc)
f str []
How can I know if the F# compiler turned it into a loop? Is there a way to find out without using Reflector (I have no experience with Reflector and I Don't know C#)?
Edit: Also, is it possible to write a tail recursive function without using an inner function, or is it necessary for the loop to reside in?
Also, Is there a function in F# std lib to run a given function a number of times, each time giving it the last output as input? Lets say I have a string, I want to run a function over the string then run it again over the resultant string and so on...
Edit: Since F# 8 there is a way with the [<TailCall>]
attribute, see this answer: https://stackoverflow.com/a/77532717/969070
Original answer:
Unfortunately there is no trivial way.
It is not too hard to read the source code and use the types and determine whether something is a tail call by inspection (is it 'the last thing', and not in a 'try' block), but people second-guess themselves and make mistakes. There's no simple automated way (other than e.g. inspecting the generated code).
Of course, you can just try your function on a large piece of test data and see if it blows up or not.
The F# compiler will generate .tail IL instructions for all tail calls (unless the compiler flags to turn them off is used - used for when you want to keep stack frames for debugging), with the exception that directly tail-recursive functions will be optimized into loops. (EDIT: I think nowadays the F# compiler also fails to emit .tail in cases where it can prove there are no recursive loops through this call site; this is an optimization given that the .tail opcode is a little slower on many platforms.)
'tailcall' is a reserved keyword, with the idea that a future version of F# may allow you to write e.g.
tailcall func args
and then get a warning/error if it's not a tail call.
Only functions that are not naturally tail-recursive (and thus need an extra accumulator parameter) will 'force' you into the 'inner function' idiom.
Here's a code sample of what you asked:
let rec nTimes n f x =
if n = 0 then
x
else
nTimes (n-1) f (f x)
let r = nTimes 3 (fun s -> s ^ " is a rose") "A rose"
printfn "%s" r