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windowsbatch-file

How assign the current day to a batch file variable and change the date?

I would like a script to execute:

date 01/DD/2017

Where DD is the current day of MM/DD/YYY

date /t returns: MM/DD/YYYY ^^^^^^^ 0123456 I think that:

%DATE:~3,% returns DD

How to assign the output of characters 3-4 to the variable DD and execute date 01/DD/2017? DD is a the two digit number of the current day.

Solution

  • you can maybe do something like:

    @echo off
for /f "tokens=1" %%a in ('date /t') do set currentdate=%%a

set DD=%currentdate:~3,2%

date 01/%DD%/2017

echo new date is set to 01/%DD%/2017

    or simply:

    date 01/%date:~3,2%/2017

    the same thing on linux in case someone need it you can do:

    #!/bin/bash
DD=$(date +%d)
echo "01/$DD/2017"

    I hope this help you bro.