Search code examples
androidlistviewsmooth-scrolling

Wait unitl ListView's smoothScrollToPosition() finishes


Scope

I need to scroll to certain position smoothly and then "jump" to another position with setSelection(anotherPosition). This is done to create an illusion of smooth scrolling of (e.g.) 100 items in ListView. smoothScrollToPosition(100) lasts too much, you know.

Problem

setSelection() doesn't wait till smoothScrollToPosition finishes its work, so setSelection() is being called immediately and user sees quick jumping only;

Code

private final int scrollableItems = 20;

int firstVisiblePosition = mListView.getFirstVisiblePosition();
if (firstVisiblePosition < scrollableItems) {
    mListView.smoothScrollToPosition(0);
} else {
    mListView.smoothScrollToPosition(firstVisiblePosition - scrollableItems);
    mListView.setSelection(0);
}
mListView.clearFocus();

Idea

OK, we could change logic of smoothness illusion: first setSelection(), then scroll smoothly (we're scrolling to the very first item on top of the list):

    int firstVisiblePosition = mListView.getFirstVisiblePosition();

    if (firstVisiblePosition < scrollableItems) {
        mListView.smoothScrollToPosition(0);
    } else {
        mListView.setSelection(scrollableItems);
        mListView.smoothScrollToPosition(0);
    }
    mListView.clearFocus();

Solution

  • final ListView listView = ...;
    View listItemView = ...;
    listView.smoothScrollBy(listItemView.getHeight() * NUMBER_OF_VIEWS, 
        DURATION * 2);
    listView.postDelayed(new Runnable() {
        public void run() {
            listView.smoothScrollBy(0, 0); // Stops the listview from overshooting.
            listView.setSelection(0);
        }
    }, DURATION);
    

    Of course, direction of the scroll etc. would need to be adjusted for your use case (go to the top of the list)

    EDIT: Old solution could overshoot if the velocity of the scroll was too high, smoothScrollBy(0,0) will stop the smooth scrolling before setting the selection properly and immediately.