I want to use Java record
s as embeddable objects with JPA. For example I want to wrap the ID in a record to make it typesafe:
@Entity
public class DemoEntity {
@EmbeddedId
private Id id = new Id(UUID.randomUUID());
@Embeddable
public static record Id(@Basic UUID value) implements Serializable {}
}
But If I try to persist it with Hibernate 5.4.32 I get the following error:
org.hibernate.InstantiationException: No default constructor for entity: : com.example.demo.DemoEntity$Id
at org.hibernate.tuple.PojoInstantiator.instantiate(PojoInstantiator.java:85) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
at org.hibernate.tuple.component.AbstractComponentTuplizer.instantiate(AbstractComponentTuplizer.java:84) ~[hibernate-core-5.4.32.Final.jar:5.4.32.Final]
...
So it looks like Hibernate would treat the record Id
like an entity, although it is an @Embeddable
.
The same happens with non-id fields and @Embedded
:
@Embedded
private Thing thing = new Thing("example");
@Embeddable
public static record Thing(@Basic String value) implements Serializable {}
Is there a way to use @Embeddable record
s with JPA/Hibernate?
Now supported.
According to this post, What is new in Jakarta Persistence 3.2 by F.Marchioni of 2024-11, Jakarta Persistence 3.2 (part of Jakarta EE 11) allows Java records to be used as embeddable entities.
His code example defining a record
as Embeddable
.
import jakarta.persistence.Embeddable;
@Embeddable
public record Employee(String name, String department, long salary) {}
And embedding that record
in an Entity
.
import jakarta.persistence.Entity;
import jakarta.persistence.Id;
@Entity
public class Company {
@Id
private Long id;
private Employee employee;
// Constructors, getters, and setters (if needed)
}