Getting the module and class of currently executing classmethod in Python

For code that exists in a module named some.module and looks like this:

class MyClass:

 @classmethod
 def method(cls):
  # do something
  pass

I'd like to know in the block marked as "do something" what the module name, the class name, and the method name are. In the above example, that would be:

module some.module
class MyClass
method method

I know of inspect.stack() and I can get the function / method name from it, but I can't find the rest of the data.

Solution

These are the most direct ways:

import inspect

class MyClass:

 @classmethod
 def method(cls):
  print("module:", __name__)
  print("class:", cls.__name__)
  print("method:", inspect.currentframe().f_code.co_name)

Doing the same from a utility function requires traversing "back" (up) in the call stack to find the calling frame:

import inspect

def dbg():
    frame = inspect.currentframe().f_back
    print("module:", frame.f_globals.get("__name__"))
    print("cls:", frame.f_locals.get("cls"))
    print("method:", frame.f_code.co_name)